# 2022-06-27

## [112. Path Sum](https://leetcode.com/problems/path-sum/)

### Description

Given the `root` of a binary tree and an integer `targetSum`, return `true` if the tree has a **root-to-leaf** path such that adding up all the values along the path equals `targetSum`.

A **leaf** is a node with no children.

**Example 1:**

![](https://img.content.cc/a/2022/06/27/11-13-10-134-742c651c576f3ecd182f1ad76ef48299-d4ba03.png)

```
Input: root = [5,4,8,11,null,13,4,7,2,null,null,null,1], targetSum = 22
Output: true
Explanation: The root-to-leaf path with the target sum is shown.
```

**Example 2:**

![](https://img.content.cc/a/2022/06/27/11-13-20-136-9e59eea0963a921ebdc0f48f2e375e29-46f9d3.png)

```
Input: root = [1,2,3], targetSum = 5
Output: false
Explanation: There two root-to-leaf paths in the tree:
(1 --> 2): The sum is 3.
(1 --> 3): The sum is 4.
There is no root-to-leaf path with sum = 5.
```

**Example 3:**

```
Input: root = [], targetSum = 0
Output: false
Explanation: Since the tree is empty, there are no root-to-leaf paths.
```

**Constraints:**

* The number of nodes in the tree is in the range `[0, 5000]`.
* `-1000 <= Node.val <= 1000`
* `-1000 <= targetSum <= 1000`

### Solution

#### Approach #0: DFS

```go
/**
 * Definition for a binary tree node.
 * type TreeNode struct {
 *     Val int
 *     Left *TreeNode
 *     Right *TreeNode
 * }
 */
func hasPathSum(root *TreeNode, targetSum int) bool {
    if root == nil {
        return false
    }
    if root.Left == nil && root.Right == nil {
        return root.Val == targetSum
    }
    return hasPathSum(root.Left, targetSum-root.Val) || hasPathSum(root.Right, targetSum-root.Val)
}
```

#### Approach #1: BFS

```go
/**
 * Definition for a binary tree node.
 * type TreeNode struct {
 *     Val int
 *     Left *TreeNode
 *     Right *TreeNode
 * }
 */
func hasPathSum(root *TreeNode, targetSum int) bool {
    if root == nil {
        return false
    }
    nodeQ := []*TreeNode{root}
    valQ := []int{0}
    for len(nodeQ) > 0 {
        node := nodeQ[0]
        nodeQ = nodeQ[1:]
        val := valQ[0]
        valQ = valQ[1:]
        if node.Left == nil && node.Right == nil && val+node.Val == targetSum {
            return true
        }
        if node.Left != nil {
            nodeQ = append(nodeQ, node.Left)
            valQ = append(valQ, node.Val+val)
        }
        if node.Right != nil {
            nodeQ = append(nodeQ, node.Right)
            valQ = append(valQ, node.Val+val)
        }
    }
    return false
}
```


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