2022-06-25

66. Plus One

Description

You are given a large integer represented as an integer array `digits`, where each `digits[i]` is the `ith` digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading `0`'s.

Increment the large integer by one and return the resulting array of digits.

Example 1:

``````Input: digits = [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].``````

Example 2:

``````Input: digits = [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.
Incrementing by one gives 4321 + 1 = 4322.
Thus, the result should be [4,3,2,2].``````

Example 3:

``````Input: digits = [9]
Output: [1,0]
Explanation: The array represents the integer 9.
Incrementing by one gives 9 + 1 = 10.
Thus, the result should be [1,0].``````

Constraints:

• `1 <= digits.length <= 100`

• `0 <= digits[i] <= 9`

• `digits` does not contain any leading `0`'s.

Solution

Approach #0

``````func plusOne(digits []int) []int {
digits[len(digits)-1]++
for i := len(digits) - 1; i >= 0; i-- {
if i > 0 {
if digits[i] >= 10 {
digits[i] -= 10
digits[i-1]++
}
} else {
if digits[i] >= 10 {
digits[i] -= 10
digits = append([]int{1}, digits...)
}
}
}
return digits
}``````

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